3.311 \(\int \frac {1}{x^{7/2} (a+b x^2)^3} \, dx\)

Optimal. Leaf size=264 \[ \frac {117 b^{5/4} \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{64 \sqrt {2} a^{17/4}}-\frac {117 b^{5/4} \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{64 \sqrt {2} a^{17/4}}-\frac {117 b^{5/4} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{32 \sqrt {2} a^{17/4}}+\frac {117 b^{5/4} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}+1\right )}{32 \sqrt {2} a^{17/4}}+\frac {117 b}{16 a^4 \sqrt {x}}-\frac {117}{80 a^3 x^{5/2}}+\frac {13}{16 a^2 x^{5/2} \left (a+b x^2\right )}+\frac {1}{4 a x^{5/2} \left (a+b x^2\right )^2} \]

[Out]

-117/80/a^3/x^(5/2)+1/4/a/x^(5/2)/(b*x^2+a)^2+13/16/a^2/x^(5/2)/(b*x^2+a)-117/64*b^(5/4)*arctan(1-b^(1/4)*2^(1
/2)*x^(1/2)/a^(1/4))/a^(17/4)*2^(1/2)+117/64*b^(5/4)*arctan(1+b^(1/4)*2^(1/2)*x^(1/2)/a^(1/4))/a^(17/4)*2^(1/2
)+117/128*b^(5/4)*ln(a^(1/2)+x*b^(1/2)-a^(1/4)*b^(1/4)*2^(1/2)*x^(1/2))/a^(17/4)*2^(1/2)-117/128*b^(5/4)*ln(a^
(1/2)+x*b^(1/2)+a^(1/4)*b^(1/4)*2^(1/2)*x^(1/2))/a^(17/4)*2^(1/2)+117/16*b/a^4/x^(1/2)

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Rubi [A]  time = 0.21, antiderivative size = 264, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 9, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.600, Rules used = {290, 325, 329, 297, 1162, 617, 204, 1165, 628} \[ \frac {117 b^{5/4} \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{64 \sqrt {2} a^{17/4}}-\frac {117 b^{5/4} \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {a}+\sqrt {b} x\right )}{64 \sqrt {2} a^{17/4}}-\frac {117 b^{5/4} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{32 \sqrt {2} a^{17/4}}+\frac {117 b^{5/4} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}+1\right )}{32 \sqrt {2} a^{17/4}}+\frac {13}{16 a^2 x^{5/2} \left (a+b x^2\right )}+\frac {117 b}{16 a^4 \sqrt {x}}-\frac {117}{80 a^3 x^{5/2}}+\frac {1}{4 a x^{5/2} \left (a+b x^2\right )^2} \]

Antiderivative was successfully verified.

[In]

Int[1/(x^(7/2)*(a + b*x^2)^3),x]

[Out]

-117/(80*a^3*x^(5/2)) + (117*b)/(16*a^4*Sqrt[x]) + 1/(4*a*x^(5/2)*(a + b*x^2)^2) + 13/(16*a^2*x^(5/2)*(a + b*x
^2)) - (117*b^(5/4)*ArcTan[1 - (Sqrt[2]*b^(1/4)*Sqrt[x])/a^(1/4)])/(32*Sqrt[2]*a^(17/4)) + (117*b^(5/4)*ArcTan
[1 + (Sqrt[2]*b^(1/4)*Sqrt[x])/a^(1/4)])/(32*Sqrt[2]*a^(17/4)) + (117*b^(5/4)*Log[Sqrt[a] - Sqrt[2]*a^(1/4)*b^
(1/4)*Sqrt[x] + Sqrt[b]*x])/(64*Sqrt[2]*a^(17/4)) - (117*b^(5/4)*Log[Sqrt[a] + Sqrt[2]*a^(1/4)*b^(1/4)*Sqrt[x]
+ Sqrt[b]*x])/(64*Sqrt[2]*a^(17/4))

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 290

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(
a*c*n*(p + 1)), x] + Dist[(m + n*(p + 1) + 1)/(a*n*(p + 1)), Int[(c*x)^m*(a + b*x^n)^(p + 1), x], x] /; FreeQ[
{a, b, c, m}, x] && IGtQ[n, 0] && LtQ[p, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 297

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]},
Dist[1/(2*s), Int[(r + s*x^2)/(a + b*x^4), x], x] - Dist[1/(2*s), Int[(r - s*x^2)/(a + b*x^4), x], x]] /; Free
Q[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ,
b]]))

Rule 325

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a*
c*(m + 1)), x] - Dist[(b*(m + n*(p + 1) + 1))/(a*c^n*(m + 1)), Int[(c*x)^(m + n)*(a + b*x^n)^p, x], x] /; Free
Q[{a, b, c, p}, x] && IGtQ[n, 0] && LtQ[m, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 329

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + (b*x^(k*n))/c^n)^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1162

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(2*d)/e, 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 1165

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(-2*d)/e, 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rubi steps

\begin {align*} \int \frac {1}{x^{7/2} \left (a+b x^2\right )^3} \, dx &=\frac {1}{4 a x^{5/2} \left (a+b x^2\right )^2}+\frac {13 \int \frac {1}{x^{7/2} \left (a+b x^2\right )^2} \, dx}{8 a}\\ &=\frac {1}{4 a x^{5/2} \left (a+b x^2\right )^2}+\frac {13}{16 a^2 x^{5/2} \left (a+b x^2\right )}+\frac {117 \int \frac {1}{x^{7/2} \left (a+b x^2\right )} \, dx}{32 a^2}\\ &=-\frac {117}{80 a^3 x^{5/2}}+\frac {1}{4 a x^{5/2} \left (a+b x^2\right )^2}+\frac {13}{16 a^2 x^{5/2} \left (a+b x^2\right )}-\frac {(117 b) \int \frac {1}{x^{3/2} \left (a+b x^2\right )} \, dx}{32 a^3}\\ &=-\frac {117}{80 a^3 x^{5/2}}+\frac {117 b}{16 a^4 \sqrt {x}}+\frac {1}{4 a x^{5/2} \left (a+b x^2\right )^2}+\frac {13}{16 a^2 x^{5/2} \left (a+b x^2\right )}+\frac {\left (117 b^2\right ) \int \frac {\sqrt {x}}{a+b x^2} \, dx}{32 a^4}\\ &=-\frac {117}{80 a^3 x^{5/2}}+\frac {117 b}{16 a^4 \sqrt {x}}+\frac {1}{4 a x^{5/2} \left (a+b x^2\right )^2}+\frac {13}{16 a^2 x^{5/2} \left (a+b x^2\right )}+\frac {\left (117 b^2\right ) \operatorname {Subst}\left (\int \frac {x^2}{a+b x^4} \, dx,x,\sqrt {x}\right )}{16 a^4}\\ &=-\frac {117}{80 a^3 x^{5/2}}+\frac {117 b}{16 a^4 \sqrt {x}}+\frac {1}{4 a x^{5/2} \left (a+b x^2\right )^2}+\frac {13}{16 a^2 x^{5/2} \left (a+b x^2\right )}-\frac {\left (117 b^{3/2}\right ) \operatorname {Subst}\left (\int \frac {\sqrt {a}-\sqrt {b} x^2}{a+b x^4} \, dx,x,\sqrt {x}\right )}{32 a^4}+\frac {\left (117 b^{3/2}\right ) \operatorname {Subst}\left (\int \frac {\sqrt {a}+\sqrt {b} x^2}{a+b x^4} \, dx,x,\sqrt {x}\right )}{32 a^4}\\ &=-\frac {117}{80 a^3 x^{5/2}}+\frac {117 b}{16 a^4 \sqrt {x}}+\frac {1}{4 a x^{5/2} \left (a+b x^2\right )^2}+\frac {13}{16 a^2 x^{5/2} \left (a+b x^2\right )}+\frac {(117 b) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {x}\right )}{64 a^4}+\frac {(117 b) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {x}\right )}{64 a^4}+\frac {\left (117 b^{5/4}\right ) \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}+2 x}{-\frac {\sqrt {a}}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {x}\right )}{64 \sqrt {2} a^{17/4}}+\frac {\left (117 b^{5/4}\right ) \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{b}}-2 x}{-\frac {\sqrt {a}}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {x}\right )}{64 \sqrt {2} a^{17/4}}\\ &=-\frac {117}{80 a^3 x^{5/2}}+\frac {117 b}{16 a^4 \sqrt {x}}+\frac {1}{4 a x^{5/2} \left (a+b x^2\right )^2}+\frac {13}{16 a^2 x^{5/2} \left (a+b x^2\right )}+\frac {117 b^{5/4} \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{64 \sqrt {2} a^{17/4}}-\frac {117 b^{5/4} \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{64 \sqrt {2} a^{17/4}}+\frac {\left (117 b^{5/4}\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{32 \sqrt {2} a^{17/4}}-\frac {\left (117 b^{5/4}\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{32 \sqrt {2} a^{17/4}}\\ &=-\frac {117}{80 a^3 x^{5/2}}+\frac {117 b}{16 a^4 \sqrt {x}}+\frac {1}{4 a x^{5/2} \left (a+b x^2\right )^2}+\frac {13}{16 a^2 x^{5/2} \left (a+b x^2\right )}-\frac {117 b^{5/4} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{32 \sqrt {2} a^{17/4}}+\frac {117 b^{5/4} \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x}}{\sqrt [4]{a}}\right )}{32 \sqrt {2} a^{17/4}}+\frac {117 b^{5/4} \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{64 \sqrt {2} a^{17/4}}-\frac {117 b^{5/4} \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}+\sqrt {b} x\right )}{64 \sqrt {2} a^{17/4}}\\ \end {align*}

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Mathematica [C]  time = 0.01, size = 29, normalized size = 0.11 \[ -\frac {2 \, _2F_1\left (-\frac {5}{4},3;-\frac {1}{4};-\frac {b x^2}{a}\right )}{5 a^3 x^{5/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(x^(7/2)*(a + b*x^2)^3),x]

[Out]

(-2*Hypergeometric2F1[-5/4, 3, -1/4, -((b*x^2)/a)])/(5*a^3*x^(5/2))

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fricas [A]  time = 0.76, size = 306, normalized size = 1.16 \[ -\frac {2340 \, {\left (a^{4} b^{2} x^{7} + 2 \, a^{5} b x^{5} + a^{6} x^{3}\right )} \left (-\frac {b^{5}}{a^{17}}\right )^{\frac {1}{4}} \arctan \left (-\frac {1601613 \, a^{4} b^{4} \sqrt {x} \left (-\frac {b^{5}}{a^{17}}\right )^{\frac {1}{4}} - \sqrt {-2565164201769 \, a^{9} b^{5} \sqrt {-\frac {b^{5}}{a^{17}}} + 2565164201769 \, b^{8} x} a^{4} \left (-\frac {b^{5}}{a^{17}}\right )^{\frac {1}{4}}}{1601613 \, b^{5}}\right ) - 585 \, {\left (a^{4} b^{2} x^{7} + 2 \, a^{5} b x^{5} + a^{6} x^{3}\right )} \left (-\frac {b^{5}}{a^{17}}\right )^{\frac {1}{4}} \log \left (1601613 \, a^{13} \left (-\frac {b^{5}}{a^{17}}\right )^{\frac {3}{4}} + 1601613 \, b^{4} \sqrt {x}\right ) + 585 \, {\left (a^{4} b^{2} x^{7} + 2 \, a^{5} b x^{5} + a^{6} x^{3}\right )} \left (-\frac {b^{5}}{a^{17}}\right )^{\frac {1}{4}} \log \left (-1601613 \, a^{13} \left (-\frac {b^{5}}{a^{17}}\right )^{\frac {3}{4}} + 1601613 \, b^{4} \sqrt {x}\right ) - 4 \, {\left (585 \, b^{3} x^{6} + 1053 \, a b^{2} x^{4} + 416 \, a^{2} b x^{2} - 32 \, a^{3}\right )} \sqrt {x}}{320 \, {\left (a^{4} b^{2} x^{7} + 2 \, a^{5} b x^{5} + a^{6} x^{3}\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(7/2)/(b*x^2+a)^3,x, algorithm="fricas")

[Out]

-1/320*(2340*(a^4*b^2*x^7 + 2*a^5*b*x^5 + a^6*x^3)*(-b^5/a^17)^(1/4)*arctan(-1/1601613*(1601613*a^4*b^4*sqrt(x
)*(-b^5/a^17)^(1/4) - sqrt(-2565164201769*a^9*b^5*sqrt(-b^5/a^17) + 2565164201769*b^8*x)*a^4*(-b^5/a^17)^(1/4)
)/b^5) - 585*(a^4*b^2*x^7 + 2*a^5*b*x^5 + a^6*x^3)*(-b^5/a^17)^(1/4)*log(1601613*a^13*(-b^5/a^17)^(3/4) + 1601
613*b^4*sqrt(x)) + 585*(a^4*b^2*x^7 + 2*a^5*b*x^5 + a^6*x^3)*(-b^5/a^17)^(1/4)*log(-1601613*a^13*(-b^5/a^17)^(
3/4) + 1601613*b^4*sqrt(x)) - 4*(585*b^3*x^6 + 1053*a*b^2*x^4 + 416*a^2*b*x^2 - 32*a^3)*sqrt(x))/(a^4*b^2*x^7
+ 2*a^5*b*x^5 + a^6*x^3)

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giac [A]  time = 0.63, size = 232, normalized size = 0.88 \[ \frac {117 \, \sqrt {2} \left (a b^{3}\right )^{\frac {3}{4}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a}{b}\right )^{\frac {1}{4}} + 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{64 \, a^{5} b} + \frac {117 \, \sqrt {2} \left (a b^{3}\right )^{\frac {3}{4}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a}{b}\right )^{\frac {1}{4}} - 2 \, \sqrt {x}\right )}}{2 \, \left (\frac {a}{b}\right )^{\frac {1}{4}}}\right )}{64 \, a^{5} b} - \frac {117 \, \sqrt {2} \left (a b^{3}\right )^{\frac {3}{4}} \log \left (\sqrt {2} \sqrt {x} \left (\frac {a}{b}\right )^{\frac {1}{4}} + x + \sqrt {\frac {a}{b}}\right )}{128 \, a^{5} b} + \frac {117 \, \sqrt {2} \left (a b^{3}\right )^{\frac {3}{4}} \log \left (-\sqrt {2} \sqrt {x} \left (\frac {a}{b}\right )^{\frac {1}{4}} + x + \sqrt {\frac {a}{b}}\right )}{128 \, a^{5} b} + \frac {21 \, b^{3} x^{\frac {7}{2}} + 25 \, a b^{2} x^{\frac {3}{2}}}{16 \, {\left (b x^{2} + a\right )}^{2} a^{4}} + \frac {2 \, {\left (15 \, b x^{2} - a\right )}}{5 \, a^{4} x^{\frac {5}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(7/2)/(b*x^2+a)^3,x, algorithm="giac")

[Out]

117/64*sqrt(2)*(a*b^3)^(3/4)*arctan(1/2*sqrt(2)*(sqrt(2)*(a/b)^(1/4) + 2*sqrt(x))/(a/b)^(1/4))/(a^5*b) + 117/6
4*sqrt(2)*(a*b^3)^(3/4)*arctan(-1/2*sqrt(2)*(sqrt(2)*(a/b)^(1/4) - 2*sqrt(x))/(a/b)^(1/4))/(a^5*b) - 117/128*s
qrt(2)*(a*b^3)^(3/4)*log(sqrt(2)*sqrt(x)*(a/b)^(1/4) + x + sqrt(a/b))/(a^5*b) + 117/128*sqrt(2)*(a*b^3)^(3/4)*
log(-sqrt(2)*sqrt(x)*(a/b)^(1/4) + x + sqrt(a/b))/(a^5*b) + 1/16*(21*b^3*x^(7/2) + 25*a*b^2*x^(3/2))/((b*x^2 +
a)^2*a^4) + 2/5*(15*b*x^2 - a)/(a^4*x^(5/2))

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maple [A]  time = 0.02, size = 192, normalized size = 0.73 \[ \frac {21 b^{3} x^{\frac {7}{2}}}{16 \left (b \,x^{2}+a \right )^{2} a^{4}}+\frac {25 b^{2} x^{\frac {3}{2}}}{16 \left (b \,x^{2}+a \right )^{2} a^{3}}+\frac {117 \sqrt {2}\, b \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}-1\right )}{64 \left (\frac {a}{b}\right )^{\frac {1}{4}} a^{4}}+\frac {117 \sqrt {2}\, b \arctan \left (\frac {\sqrt {2}\, \sqrt {x}}{\left (\frac {a}{b}\right )^{\frac {1}{4}}}+1\right )}{64 \left (\frac {a}{b}\right )^{\frac {1}{4}} a^{4}}+\frac {117 \sqrt {2}\, b \ln \left (\frac {x -\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \sqrt {x}+\sqrt {\frac {a}{b}}}{x +\left (\frac {a}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \sqrt {x}+\sqrt {\frac {a}{b}}}\right )}{128 \left (\frac {a}{b}\right )^{\frac {1}{4}} a^{4}}+\frac {6 b}{a^{4} \sqrt {x}}-\frac {2}{5 a^{3} x^{\frac {5}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^(7/2)/(b*x^2+a)^3,x)

[Out]

-2/5/a^3/x^(5/2)+6*b/a^4/x^(1/2)+21/16/a^4*b^3/(b*x^2+a)^2*x^(7/2)+25/16/a^3*b^2/(b*x^2+a)^2*x^(3/2)+117/128/a
^4*b/(a/b)^(1/4)*2^(1/2)*ln((x-(a/b)^(1/4)*2^(1/2)*x^(1/2)+(a/b)^(1/2))/(x+(a/b)^(1/4)*2^(1/2)*x^(1/2)+(a/b)^(
1/2)))+117/64/a^4*b/(a/b)^(1/4)*2^(1/2)*arctan(2^(1/2)/(a/b)^(1/4)*x^(1/2)+1)+117/64/a^4*b/(a/b)^(1/4)*2^(1/2)
*arctan(2^(1/2)/(a/b)^(1/4)*x^(1/2)-1)

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maxima [A]  time = 3.05, size = 243, normalized size = 0.92 \[ \frac {585 \, b^{3} x^{6} + 1053 \, a b^{2} x^{4} + 416 \, a^{2} b x^{2} - 32 \, a^{3}}{80 \, {\left (a^{4} b^{2} x^{\frac {13}{2}} + 2 \, a^{5} b x^{\frac {9}{2}} + a^{6} x^{\frac {5}{2}}\right )}} + \frac {117 \, b^{2} {\left (\frac {2 \, \sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} + 2 \, \sqrt {b} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b}}}\right )}{\sqrt {\sqrt {a} \sqrt {b}} \sqrt {b}} + \frac {2 \, \sqrt {2} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} - 2 \, \sqrt {b} \sqrt {x}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b}}}\right )}{\sqrt {\sqrt {a} \sqrt {b}} \sqrt {b}} - \frac {\sqrt {2} \log \left (\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} \sqrt {x} + \sqrt {b} x + \sqrt {a}\right )}{a^{\frac {1}{4}} b^{\frac {3}{4}}} + \frac {\sqrt {2} \log \left (-\sqrt {2} a^{\frac {1}{4}} b^{\frac {1}{4}} \sqrt {x} + \sqrt {b} x + \sqrt {a}\right )}{a^{\frac {1}{4}} b^{\frac {3}{4}}}\right )}}{128 \, a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(7/2)/(b*x^2+a)^3,x, algorithm="maxima")

[Out]

1/80*(585*b^3*x^6 + 1053*a*b^2*x^4 + 416*a^2*b*x^2 - 32*a^3)/(a^4*b^2*x^(13/2) + 2*a^5*b*x^(9/2) + a^6*x^(5/2)
) + 117/128*b^2*(2*sqrt(2)*arctan(1/2*sqrt(2)*(sqrt(2)*a^(1/4)*b^(1/4) + 2*sqrt(b)*sqrt(x))/sqrt(sqrt(a)*sqrt(
b)))/(sqrt(sqrt(a)*sqrt(b))*sqrt(b)) + 2*sqrt(2)*arctan(-1/2*sqrt(2)*(sqrt(2)*a^(1/4)*b^(1/4) - 2*sqrt(b)*sqrt
(x))/sqrt(sqrt(a)*sqrt(b)))/(sqrt(sqrt(a)*sqrt(b))*sqrt(b)) - sqrt(2)*log(sqrt(2)*a^(1/4)*b^(1/4)*sqrt(x) + sq
rt(b)*x + sqrt(a))/(a^(1/4)*b^(3/4)) + sqrt(2)*log(-sqrt(2)*a^(1/4)*b^(1/4)*sqrt(x) + sqrt(b)*x + sqrt(a))/(a^
(1/4)*b^(3/4)))/a^4

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mupad [B]  time = 4.65, size = 109, normalized size = 0.41 \[ \frac {\frac {26\,b\,x^2}{5\,a^2}-\frac {2}{5\,a}+\frac {1053\,b^2\,x^4}{80\,a^3}+\frac {117\,b^3\,x^6}{16\,a^4}}{a^2\,x^{5/2}+b^2\,x^{13/2}+2\,a\,b\,x^{9/2}}-\frac {117\,{\left (-b\right )}^{5/4}\,\mathrm {atan}\left (\frac {{\left (-b\right )}^{1/4}\,\sqrt {x}}{a^{1/4}}\right )}{32\,a^{17/4}}+\frac {117\,{\left (-b\right )}^{5/4}\,\mathrm {atanh}\left (\frac {{\left (-b\right )}^{1/4}\,\sqrt {x}}{a^{1/4}}\right )}{32\,a^{17/4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^(7/2)*(a + b*x^2)^3),x)

[Out]

((26*b*x^2)/(5*a^2) - 2/(5*a) + (1053*b^2*x^4)/(80*a^3) + (117*b^3*x^6)/(16*a^4))/(a^2*x^(5/2) + b^2*x^(13/2)
+ 2*a*b*x^(9/2)) - (117*(-b)^(5/4)*atan(((-b)^(1/4)*x^(1/2))/a^(1/4)))/(32*a^(17/4)) + (117*(-b)^(5/4)*atanh((
(-b)^(1/4)*x^(1/2))/a^(1/4)))/(32*a^(17/4))

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**(7/2)/(b*x**2+a)**3,x)

[Out]

Timed out

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